因式分解:m(m-1)x^2 - (2m^2 -1)x + m(m+1) =0[mx - ( m +1 )] [(m-1)x -m_数学解答

因式分解:m(m-1)x^2 - (2m^2 -1)x + m(m+1) =0
[mx - ( m +1 )] [(m-1)x -m]=0
怎么得出的...
如果是十字相乘...m + (m+1) 怎么等于 -(2m^2 -1)

人气：410 ℃　时间：2020-05-26 16:36:15

解答

十字相乘 m-( m+1 )
m-1-m
-m*mx-(m+1)(m-1)x
=-m^2x-(m^2-1)x
=(-m^2-m^2+1)x
=-(2m^2-1)x