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数学
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先化简,再求值:(x-y分之一+x+y分之一)÷x的平方-y的平方分之x的平方y,其中x=根号3+1,y=根号3-1
人气:221 ℃ 时间:2019-08-23 06:34:53
解答
[1/(x-y)+1/(x+y)]÷(x^2y)/(x^2-y^2)
=[(x+y+x-y)/(x-y)(x+y)]÷(x^2y)/(x+y)(x-y)
=[2x/(x-y)(x+y)]÷(x^2y)/(x+y)(x-y)
=2x/(x^2y)
=2/(xy)
=2/[(√3+1)×(√3-1)]
=2/2
=1
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