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lim xlnx (x->+0)
人气:419 ℃ 时间:2020-06-18 00:43:51
解答
lim(x→0+) xlnx
=lim(x→0+) lnx/(1/x)
=lim(x→0+) (1/x)/(-1/x^2)
=lim(x→0+) -x
=0limarctan(1/1-x), (x->1-0)limarctan(1/1-x)=π/2, (x->1-0)
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