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复数(1+i)^10/1-i等于?
人气:162 ℃ 时间:2020-09-16 04:55:39
解答
(1+i)^2=(1-1+2i)=2i
(1+i)^10 = (2i)^5 = 32i
(1+i)^10/(1-i) = 32i*(1+i) / [(1-i)(1+i)] = (32i-32) /2 = 16i-16
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