(3x^2+1/2y-2/3y^2)*(-1/2xy)^3
人气：462 ℃ 时间：2019-10-11 06:49:31
解答
原式=(3x^2+1/2y-2/3y^2)*(-1/8x^3y^3)
=3x^2*(-1/8x^3y^3)+1/2y*(-1/8x^3y^3)-2/3y^2*(-1/8x^3y^3)
=-3/8x^5y^3)-1/16x^3y^4+1/12x^3y^4
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