x=3
aX∧5+bX∧3+cX+d
=a×3∧5+b×3∧3+c×3+d
=-4
x=-3
aX∧5+bX∧3+cX-d
=a×(-3)∧5+b×(-3)∧3+c×(-3)-d
=-a×3∧5-b×3∧3-c×3-d
=-(a×3∧5+b×3∧3+c×3+d)
=-(-4)
=4