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(6x+7)^2*(3x+4)*(x+1)-6因式分解
人气:489 ℃ 时间:2019-12-08 04:59:04
解答
(6x+7)^2(3x+4)(x+1)-6=(36x²+84x+49)(3x²+7x+4)-6令a=3x²+7x+4则36x²+84x+49=12a+1∴原式=a(12a+1)-6=12a²+a-6=(3a-2)(4a+3)=(9x²+21x+10)(12x²+28x+19)=(3x+2)(3x+5)(12x²...
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