1/(m^2-m)+(m-5)/(2m^2-2)
=1/m(m-1)+(m-5)/2(m+1)(m-1)
=2(m+1)/2m(m+1)(m-1)+m(m-5)/2m(m+1)(m-1)
=[2(m+1)+m(m-5)]/2m(m+1)(m-1)
=(m^2-3m+2)/2m(m+1)(m-1)
=(m-1)(m+3)/2m(m+1)(m-1)
=(m+3)/2m(m+1)