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设p=1/log2(11)+1/log3(11)+1/log4(11)+1/log5(11),则 A.0<p<1 B.1<p<2 C.2<p<3 D.3<p<4
请问具体解法?ps:2,3,4,5都是底数,11是真数
人气:143 ℃ 时间:2019-11-02 00:26:31
解答
选B.1<p<2
利用loga(b)=1/logb(a)
p=1/log2(11)+1/log3(11)+1/log4(11)+1/log5(11)
=log11(2)+log11(2)+log11(2)+log11(5)
=log11(2*3*4*5)
=log11(120)
11<120<121=11^2
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