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设 z=xyf(y/x),f(u)可导,则xZ'x+yZ'y=?
(Z'x表示对x求导)
人气:223 ℃ 时间:2020-05-19 00:58:50
解答
Z'x=-yf'(y/x)y/x^2
xZ'=-y^2f'(y/x)/x
Z'y=xf'(y/x)1/x
yZ'y=yf'(y/x)
xZ'x+yZ'y
=-y^2f'(y/x)/x+yf'(y/x)
=y(x-y)f'(y/x)/x
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