由洛必达法则,lim (x→0) (2^x +3^x -2) /x = lim (x→0) [(2^x) (ln 2)+(3^x) (ln 3) ] /1= ln6.= = = = = = = = =如果没学洛必达法则,但学了等价无穷小量,见解法2.解法2：因为 lim (t→0) (e^t -1) /t =1,令 t =x ...