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计算不定积分∫xcos(x/2)dx 求过程跟答案
人气:453 ℃ 时间:2020-06-27 08:47:05
解答
∫xcos(x/2)dx
=2∫xcos(x/2)d(x/2)
=2∫xdsin(x/2)
=2xsin(x/2)-2∫sin(x/2)dx
=2xsin(x/2)-4∫sin(x/2)d(x/2)
=2xsin(x/2)+4cos(x/2)+C
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