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y-3/4y-8÷(5/y-2 -y-2) 一道数学题,
人气:197 ℃ 时间:2020-10-01 07:05:52
解答
(y-3)/(4y-8)÷[5/(y-2) -(y+2)]
=(y-3)/(4y-8)÷[5-y^2+4]/(y-2).
=-(y-3)/(4y-8)*(y-2)/(y^2-9)
=-[(y-3)/4]/[(y-3)(y+3)]
=-1/[4(y+3)].
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