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复数(1-i)^2/1+i=
人气:381 ℃ 时间:2020-05-20 13:11:40
解答
(1 - i)^2/(1 + i)
= (1 - 2i - 1)/(1 + i)
= -2i/(1 + i)
= -2i(1 - i)/(1 + 1)
= -i(1 - i)
= -1 - i
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