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初一数学题求(x-1)(x^99+x^98+x^97+...+1)的值,其中x=2
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人气:435 ℃ 时间:2020-01-29 22:32:59
解答
(x-1)(x^99+x^98+x^97+...+1)
=x(x^99+x^98+x^97+...+1)-1*(x^99+x^98+x^97+...+1)
=x^100+x^99+x^98+...+x-x^99-x^98-x^97-...-1
=x^100-1
当x=2,原式=2^100-1
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