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y=-1/2cot(π/3-2x)的周期为?单调区间为?
人气:304 ℃ 时间:2020-06-03 02:42:33
解答
y=-1/2cot(π/3-2x)=1/2cot(2x-π/3)
周期T=π/2
单调区间
kπ=<2x-π/3<=(k+1)π
即kπ/2+π/6<=x<=(k+1)π/2+π/6
单调区间(kπ/2+π/6,(k+1)π/2+π/6) k=1,2,3,.
单调递减
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