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若(2a-b)零次方=1,则分式a²-3ab+2b²分之a²+2ab-b²
人气:101 ℃ 时间:2019-10-08 16:36:00
解答
(2a-b)零次方≠1 (本题改一下,否则不好做)所以2a=ba²-3ab+2b²分之a²+2ab-b²=(a²+2ab-b²)/(a²-3ab+2b²)=(a²+4a²-4a²)/(a²-6a²+8a²)=a²...
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