若代数式x2的值和代数式2x+y-1的值相等,则代数式9-2(y+2x)+2x2的值是( )
A. 7
B. 4
C. 1
D. 不能确定
人气:428 ℃ 时间:2019-11-23 09:37:32
解答
∵代数式x2的值和代数式2x+y-1的值相等,
∴x2=2x+y-1;
∴x2-(2x+y)=-1;
∴2y=2x2-4x+2
∴9-2(y+2x)+2x2=9-2y-4x+2x2=9-(2x2-4x+2)-4x+2x2=9-2x2+4x-2+2x2-4x=9-2=7.
故选A.
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