1-(tan a)-(tan b)+(tan a)(tan b)=2
(tan a)(tan b)=1+(tan a)+(tan b)
tan (a+b)
= [(tan a)+(tan b)]/[1-(tan a)(tan b)]
= -1
所以,a+b=(k-1/4)π所以答案是 3/4π吗？a、b均为钝角π
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