(2x-1)/5+(3y-2)/4=2 (1)
(3x+1)/5-(3y+2)/4=0 (2)
(1)+(2)
(2x-1+3x+1)/5+(3y-2-3y-2)/4=2
x-1=2
x=3
代入(1),1+(3y-2)/4=0
3y-2=4
y=2
x=3,y=2