√2/2sin2(x-π/4)+√6/2cos2(x-π/4)
=√2/2sin(2x-π/2)+√6/2cos(2x-π/2)
=-√2/2cos2x+√6/2sin2x
=√2(√3/2sin2x-1/2cos2x)
=√2sin(2x-π/6)打错了是√2/2sin2(x-π/4)+√6/2cos2(x-π/4)化简。。麻烦了。。是的啊，我改了，看我的解答。