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已知tanθ=-2,求sin2θ,cos2θ和tan2θ的值
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人气:277 ℃ 时间:2020-02-03 05:00:08
解答
根据万能公式
sin2θ=2tanθ/(1+tan^2θ)
=-2*2/(1+4)
=-4/5
cos2θ=(1-tan^2θ)/(1+tan^2θ)
=(1-4)/(1+4)
=-3/5
tan2θ=2tanθ/(1-tan^2θ)
=-2*2/(1-4)
=4/3
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