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(1)x^2+y^2-4x+2y+5=0,则x+2y= (2)-3x^2+6xy-3y^2
(3)因式分解的应用:解方程2x^2=3x
人气:233 ℃ 时间:2020-06-04 19:21:55
解答
(1)x²+y²-4x+2y+5=0x²-4x+4+y²+2y+1=0(x-2)²+(y+1)²=0∵(x-2)²≥0,(y+1)²≥0∴x-2=0,y+1=0∴x=2,y=-1.∴x+2y=2+2×(-1)=0(2)-3x²...
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