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(a+1分之a的2次方-a+1)除以a的2次方-1分之a
人气:213 ℃ 时间:2020-05-27 19:17:12
解答
原式=[a²/(a+1)-(a-1)]×(a²-1)/a
=[a²-(a+1)(a-1)]/(a+1)×(a+1)(a-1)/a
=(a²-a²+1)/(a+1)×(a+1)(a-1)/a
=1/(a+1)×(a+1)(a-1)/a
=(a-1)/a
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