函数y=(sinx)^2+2sinxcosx+3(cosx)^2的最小值是?
人气：199 ℃ 时间：2019-08-28 02:39:18
解答
【解】
y=(sinx)^2+2sinxcosx+3(cosx)^2
=1+2(cosx)^2+sin2x
=2+cos2x+sin2x
=2+√2sin(x+θ)
≥2-√2
最小值是2-√2
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