A)为饱和状态 B）截止状态 C）放大状态(a)和(c)怎么计算的啊A)β=501K电阻折算为50K则Ib = (12-0.7)/(10+50) = 0.1883mA
Ic = Ib *50 = 9.4mA 2K电阻上电压为 U = 9.4 * 2 = 18.8V > 12V
所以为饱和状态

C）Ib = (12-0.7)/510K = 0.0222mA
5.1K电阻电压为 U = 5.1 * 0.0222 * 50 = 5.65V < 12V
所以为放大状态