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(2+1)(22+1)(24+1)(28+1)••••••(264+1)=?用平方差公式,
人气:113 ℃ 时间:2019-11-06 10:52:56
解答
乘以(2-1)
(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
……
以此类推,最后得到
(2^64-1)(2^64+1)=2^128-1清楚了后一定采纳!
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