令y² = 2x - 1、y dy = dxx = (1 + y²)/2、x² = (1 + y²)²/4、1/x² = 4/(1 + y²)²∫ 1/[x²√(2x - 1)] dx= ∫ 4/(1 + y²)² * 1/y * y dy= 4∫ dy/(1 + y
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