∵y=(x-1)e^arctanx ∴y′=(x-1)′e^arctanx+(x-1)[e^arctanx]′=e^arctanx+(x-1)e^arctanx• [arctanx]′=e^arctanx+(x-1)e^arctanx• [1/(1+x^2)]=e^arctanx(1+(x-1)/(1+x^2))令y′=0∵e^arctanx＞0即求...