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几题分式计算
(1)2/(m-1)^2除以(1-m)
(2)(3x-6)/(x^2-4)除以(x+2)/(x^2+4x+4)
(3)(-x/y)^2*(-y^2/x)^3除以(-xy)^4
(4)(2x-6/-5x^2)^2*(x+3/x^2-6x+9)除以(x+3/x-3)^2
人气:284 ℃ 时间:2020-02-03 04:28:48
解答
(1)[2/(m-1)²] ÷ (1-m)= [2/(1-m)²] ÷ (1-m)= 2/(1-m)³(2)[(3x-6)/(x²-4)] ÷ [(x+2)/(x²+4x+4)]= {2(x-2)/[(x+2)(x-2)]} ÷ [(x+2)/(x+2)²]= [2/(x+2)] ÷ [1/(x+2)]= 2(3)[...
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