2/(x+1)+3/(x-1)=6/(x^2-1)
乘以(x^2-1)=(x+1)(x-1)得
2(x-1)+3(x+1)=6
2x-2+3x+3=6
5x=6-1
5x=5
x=1
检验：x=1时,分母为0,即x=1是增根
所以原方程无解