已知sinx-cosx=1/3,求sin2x sin^3x-cos^3x_数学解答

已知sinx-cosx=1/3,求sin2x sin^3x-cos^3x

人气：284 ℃　时间：2019-12-06 03:44:16

解答

(sinx-cosx)^2=(sinx)^2-2sinxcosx+(cosx)^2=1-sin(2x)=1/9
sin(2x)=1-1/9=8/9
(sinx)^3-(cosx)^3
=(sinx-cosx)[(sinx)^2+sinxcosx+(cosx)^2]
=(1/3)[1+sin(2x)/2]
=(1/3)(1+4/9)
=13/27