1+2-3-4+5+6-7-8+...+2001+2002-2003-2004
代数和的规律...
人气:463 ℃ 时间:2019-10-17 13:35:39
解答
1+2-3-4+5+6-7-8+...+2001+2002-2003-2004
=(1+2-3-4)+(5+6-7-8)+...+(2001+2002-2003-2004)
=(-4)+(-4)+(-4)+.+(-4)
=(-4)*2004/4
=-2004
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