n=2mol/L*0.01l=0.02mol
1.1g/cm^39%的NaOH溶液10mL(1.1*10*39%)/40=0.10725mol
n共=0.02+0.10725=0.12725mol
混合液的物质的量浓度为:0.12725mol/(0.01+0.01)=6.3625mol/L