> 数学 >
sin70度(1-根号3*tan50度)
人气:194 ℃ 时间:2020-02-06 03:03:34
解答
sin70(1-√3*tan50)
=sin70*[1+sin120*sin50/(cos120*cos50)]
=sin70*[(cos120*cos50+sin120sin50)/(cos120cos50)]
=sin70*cos(120-50)/(cos120cos50)
=sin70cos70/(cos120cos50)
=sin140/(2cos120sin40)
=1/(2cos120)
=-1
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版