角AOB=35度40分,角BOC=50度30分,角COD=21度18分,OE平分角AOD,求角BOE的度数要过程_其他解答

角AOB=35度40分,角BOC=50度30分,角COD=21度18分,OE平分角AOD,求角BOE的度数要过程

人气：398 ℃　时间：2019-10-19 18:39:38

解答

∠AOD=∠AOB+∠BOC+∠COD
=35°40'+50°30'+21°18'
=107°28'
因为OE平分∠AOD,
∠AOE=(1/2)∠AOD=107°28'/2=53°44'
所以,∠BOE=∠AOE-∠AOB
=53°44'-35°40'
=18°4