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数学
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已知a2+6a+b2-10b+34=0,求代数式(2a+b)(3a-2b)+4ab的值
人气:250 ℃ 时间:2019-10-17 07:55:36
解答
a²+6a+b²-10b+34=0
a²+6a+9+b²-10b+25=0
(a+3)²+(b-5)²=0
a+3=0,b-5=0
a=-3,b=5
2a+b=2*(-3)+5=-1
3a-2b=3*(-3)-2*(5)=-9-10=-19
ab=(-3)*5=-15
(2a+b)(3a-2b)+4ab
=(-1)*(-19)+4*(-15)
=19-60
=-41
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