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a-b=5/13 b-c=2/13 a*a+b*b+c*c=1 求ab+ac+bc
人气:454 ℃ 时间:2020-01-28 04:17:47
解答
a-b=5/13
b-c=2/13 两式相加得
a-c=7/13
a^2+b^2+c^2-(ab+bc+ac)
=[(a-b)^2+(b-c)^2+(a-c)^2]/2
=(5/13)^2+(2/13)^2+(7/13)^2
=78/169
=6/13
ab+ac+bc
=a^2+b^2+c^2-6/13
=1-6/13
=7/13
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