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((3x^2)+1)cosx的不定积分怎么做
人气:427 ℃ 时间:2020-04-22 07:19:16
解答
∫((3x^2)+1)cosxdx
=∫3x^2.dsinx + sinx
=3x^2.sinx - 6∫xsinxdx + sinx
=3x^2.sinx + 6∫xdcosx + sinx
=3x^2.sinx + 6xcosx -6∫cosxdx + sinx
=3x^2.sinx + 6xcosx -5sinx + C
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