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用0.1mol/L的NH4Cl和0.1mlo/L的氨水配置50mL,pH为10的缓冲溶液,需氨水
人气:193 ℃ 时间:2019-10-06 22:12:49
解答
PH=14-PKb+lg[NH3H2O]/[NH4+]
10=14-4.75+lg[NH3H2O]/[NH4+]
lg[NH3H2O]/[NH4+]=0.75
[NH3H2O]/[NH4+]=5.6/1
需要0.1mol/L的氨水50×5.6/6.6=42.4ml
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