解由y=x/(x^2+1)=1/(x+1/x)由f（-x）=-x/((-x)^2+1)=-x/(x^2+1)=-f（x）即f（x）是奇函数知当x＞0时,x+1/x≥2则0＜1/（x+1/x）≤1/2即0＜y≤1/2即x＞0时,函数的值域为(0,1/2]又由f（x）是奇函数故函数的值域为(0,1/2...