若|x+y+1|与√(x-y+3)互为相反数,
则|x+y+1|+√(x-y+3)=0
∴|x+y+1|=0,√(x-y+3)=0
{x+y+1=0
x-y+3=0
解得:{x=-2
y=1
∴x^y=(-2)¹=-2