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已知 g(-3)=2 g'(-3)=4
求 f'(-3) 如果 f(x) = x^2/g(x)
人气:220 ℃ 时间:2020-03-26 15:11:12
解答
f(x) = x^2/g(x)
f'(x)=[(x^2)'g(x)-x^2*g'(x)]/[g(x)]^2
=[2xg(x)-x^2*g'(x)]/[g(x)]^2
f'(-3) =
=[2*(-3)*g(-3)-(-3)^2*g'(-3)]/[g(-3)]^2
=(-6*2+9*4)/2^2
=-12
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