设x1>x2>=0
则y1-y2=(x1)^2+2x1-(x2)^2-2x2
=(x1+x2)(x1-x2)+2(x1-x2)
=(x1+x2+2)(x1-x2)>0
即y1>y2
所以y=x的平方+2x在[0,正无穷大]上是增函数