若x,y都是实数,且满足y>√1/2-x +√x-1/2 +1 化简:|x-1|-√(x-1)² - √y²-_数学解答

若x,y都是实数,且满足y>√1/2-x +√x-1/2 +1 化简:|x-1|-√(x-1)² - √y²-2y+1/y-1
√是根号+√x-1/2+1这种就是+1不在根号里
若x,y都是实数,且满足y>√1/2-x +√x-1/2 +1 化简:|x-1|-√(x-1)² - √y²-2y+1/y-1

人气：430 ℃　时间：2020-02-05 20:57:04

解答

y>√1/2-x +√x-1/2 +1先由根号得：X≥1/2,X≤1/2,所以X=1/2√(y²-2y+1)/(y-1)=√(y-1)²/(y-1)=|y-1|y>√1/2-x +√x-1/2 +1=1,y>1|x-1|-√(x-1)² - √y²-2y+1/y-1=|x-1|-|x-1|-|y-1|=-|y-1|=-(y...