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(x一y)(x^2+xy+y^2的过程多少
人气:409 ℃ 时间:2020-09-01 06:48:29
解答
(x一y)(x^2+xy+y^2)=x(x^2+xy+y^2)-y(x^2+xy+y^2)=x^3+x^2y+xy^2-yx^2-xy^2-y^3=x^3-y^3那(ab^2)^3÷(ab)^2呢(ab^2)^3÷(ab)^2=a^3*b^6/a^2*b^2=a^(3-2)*b^(6-2)=ab^4
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