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已知√x(√x+2√y)=√y(6√x-4√y)求x+√xy -y/2x+√xy+3y
是根号下xy
人气:409 ℃ 时间:2020-05-06 22:24:35
解答
√x(√x+2√y)=√y(6√x-4√y)
x-4√xy+4y=(√x-2√y)²=0
√x=2√y
x+√xy -y/2x+√xy+3y
=(x+√xy -y)/(2x+√xy+3y)
=(5y)/(11y)
=5/11大神,你分母算错了,是13yx+√xy -y/2x+√xy+3y=(x+√xy -y)/(2x+√xy+3y)=(5y)/(13y)=5/13
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