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-1^2009+(-5)^2/|-5/6|*2/5-4^2/(-2)3 ②已知|a+1|+(b-2)^2=0求(a+b)^2008+a^2009的值
人气:124 ℃ 时间:2020-05-20 06:54:06
解答
-1^2009+(-5)^2/|-5/6|*2/5-4^2/(-2)^3
=-1+25×6/5*2/5-16/(-8)
=-1+12+2
=13
②已知|a+1|+(b-2)^2=0
a+1=0 a=-1
b-2=0 b=2
(a+b)^2008+a^2009
=(-1+2)^2008+(-1)^2009
=1-1
=00.9*13/11-3.6*3/7+2.2/7/3+0.9*9/11 ②1/2-(+2/3)+4/5+(-1/2)-1/3 ③(-5)/又(-1又2/7)*0.8*(-2又1/4)/70.9*13/11-3.6*3/7+2.2/7/3+0.9*9/11=0.9*(13/11+9/11)-(3.6-2.2)*3/7=0.9*2-1.4*3/7=1.8-0.6=1.2 ②1/2-(+2/3)+4/5+(-1/2)-1/3 =1/2-1/2-2/3-1/3+4/5=-1+4/5=-1/5③(-5)/(-1又2/7)*0.8*(-2又1/4)/7=-5/(-9/7)*0.8*(-9/4)/7=-5*7/9*0.8*9/4*1/7=-1取消回答0.9*13/11-3.6*3/7+2.2/7/3+0.9*9/11=0.9*(13/11+9/11)-(3.6-2.2)*3/7=0.9*2-1.4*3/7=1.8-0.6=1.2 ②1/2-(+2/3)+4/5+(-1/2)-1/3 =1/2-1/2-2/3-1/3+4/5=-1+4/5=-1/5③(-5)/(-1又2/7)*0.8*(-2又1/4)/7=-5/(-9/7)*0.8*(-9/4)/7=-5*7/9*0.8*9/4*1/7=-1取消回答
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