已知,圆o的半径是R=10cm,弦AB平行CD,AB=6,CD=8,求AB..CD间距离
AB..CD间距离=(R^2-(AB/2)^2)^0.5-(R^2-(CD/2)^2)^0.5
=(10^2-(6/2)^2)^0.5-(10^2-(8/2)^2)^0.5
=0.374cm