连接AC
∵四边形ABCD是菱形；∠B=60°
∴△ABC和△ACD都是等边△
∴∠BAE+∠EAC=60°
∵∠EAF=60°=∠FAC+∠EAC
∴∠FAC=∠BAE=18°
∵△ABC和△ACD都是等边△
∴AB=AC；∠B=∠ACF=60°
∴△ABE≌△ACF
∴AE=AF
∵∠EAF=60°
∴△AEF是等边△
∴∠AEF=60°
∵∠AEC=∠B+∠BAC=78°
∴∠CEF=78°-60°=18°